The degree of the polynomial obtained when $x^{3} - 2 x^{2} + 23$ is subtracted from $- 18 x^{2} - 2 x + x^{3} - 14$ is ________.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 2
$(- 18 x^{2} - 2 x + x^{3} - 14) - ((x^{3} - 2 x^{2} + 23)$
$= (x^{3} - x^{3}) - (18 x^{2} - (- 2 x^{2})) - (- 2 x) - (23 - 14)$
$= (- 16 x^{2} - 2 x - 9)$
The degree of the resulting expression is 2, since the largest exponent is 2 in the resulting expression.

Suggest Corrections

Similar questions

The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is:

(x^{3} - 2) (x^{2} + 11)

x^{5} - 2 x^{2} - 3 x

x^{3} + 3 x^{2} + 1

What must be subtracted from $x^{3} - 3 x^{2} + 5 x - 1$ to get $x^{3} + 2 x^{2} - 2 x + 11$ ?

\frac{x^{3} + 2 x + 1}{5} - \frac{7}{2} x^{2} - x^{6}

x^{3}

x^{6}

Join BYJU'S Learning Program