The degree of the quotient when 6 x 3-3 x is divided by 3 x isA- 1B- 2C- 3D- 4

The correct option is B 2First factorize the dividend: 6x^3 + 3x = 6 × x × x × x + 3 × x = 3 × x (2x^2 + 1) 6(x^3) + 3x/3x = 3x(2(x^2) + 1)/3x = (2x^2 + 1) So, ...

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Standard IX

Mathematics

Taking Out Common Factors

The degree of...

Question

The degree of the quotient when $6 x^{3} + 3 x$ is divided by $3 x$ is

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Solution

The correct option is B 2
First factorize the dividend:
$6 x^{3} + 3 x$ = $6 \times x \times x \times x + 3 \times x = 3 \times x (2 x^{2} + 1)$
$\frac{6 (x^{3}) + 3 x}{3 x}$ = $\frac{3 x (2 (x^{2}) + 1)}{3 x}$
= $(2 x^{2} + 1)$
So, the degree of $2 x^{2} + 1$ is 2

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The degree of the quotient when 6x3+3x is divided by 3x is

The correct option is B 2First factorize the dividend: 6x3+3x = 6×x×x×x+3×x=3×x(2x2+1) 6(x3)+3x3x = 3x(2(x2)+1)3x = (2x2+1) So, the degree of 2x2+1 is 2

The degree of the quotient when $6 x^{3} + 3 x$ is divided by $3 x$ is

The correct option is B 2
First factorize the dividend:
$6 x^{3} + 3 x$ = $6 \times x \times x \times x + 3 \times x = 3 \times x (2 x^{2} + 1)$
$\frac{6 (x^{3}) + 3 x}{3 x}$ = $\frac{3 x (2 (x^{2}) + 1)}{3 x}$
= $(2 x^{2} + 1)$
So, the degree of $2 x^{2} + 1$ is 2