The degree of unsaturation in the given compound is:
1) $C_{3} H_{3} C l_{3}$
2) $C_{3} H_{4} O$
3) $C_{4} H_{5} N$

2, 1, 3

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1, 2, 3

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3, 2, 1

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2, 3, 1

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Solution

The correct option is B 1, 2, 3
Degree of unsaturation (DoU) $= \frac{2 C + 2 + N - X - H}{2}$
Where $C, N, X$ and $H$ are the numbers of carbons,
Nitrogen, halogens ( $F, C l, B r, I$ ) and Hydrogens respectively.
$1. C_{3} H_{3} U_{3} :$ $D o U = \frac{2 \times 3 + 2 + 0 - 3 - 3}{2} = 1$
$2. C_{3} H_{4} O :$ $D o U = \frac{2 \times 3 + 2 + 0 - 0 - 4}{2} = 2$
$3. C_{4} H_{4} N :$ $D o U = \frac{2 \times 4 + 2 + 1 - 0 - 5}{2} = 3$
Correct answer is $B . ⟹ (1, 2, 3)$

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