The degree of unsaturation or index of hydrogen deficiency in the following compounds are:
(i) $C_{6} H_{14}$ (ii) $C_{4} H_{6}$ (iii) $C_{6} H_{6}$

0, 2, 4

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1, 0, 2

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4, 1, 0

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2, 0, 4

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Solution

The correct option is A 0, 2, 4
D.U. in $C_{6} H_{14} = \frac{(2 n_{C} + 2)}{2} = \frac{14 - 14}{2} = 0^{0}$
D.U.in $C_{4} H_{6} = \frac{10 - 6}{2} = 2^{0}$
D.U. in $C_{6} H_{6} = \frac{14 - 6}{2} = 4^{0}$

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Similar questions

The degree of unsaturation or index of hydrogen deficiency in the following is:

i) $C_{6} H_{14}$

ii) $C_{4} H_{6}$

iii) $C_{6} H_{6}$

The degree of unsaturation or index of hydrogen deficiency in the following is:

i) $C_{6} H_{14}$

ii) $C_{4} H_{6}$

iii) $C_{6} H_{6}$

x + 2 y = 4

\sqrt{2}, - 3 \sqrt{2}

\begin{matrix} C u r r e n t s & r . m . s v a l u e s (1) x_{0} s i n ω t & (i) x_{0} (2) x_{0} s i n ω t c o s ω t & (i i) \frac{x_{0}}{\sqrt{2}} (3) x_{0} s i n ω t + x_{0} c o s ω t & (i i i) \frac{x_{0}}{(2 \sqrt{2})} \end{matrix}

x - 2 y = 4

(i) (0, 2) (i i) (2, 0) (i i i) (4, 0) (i v) (\sqrt 2, 4 \sqrt 2) (v) (1, 1)

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