Question

The degrees of freedom for the planar linkage shown in figure below is

• A. 1
• B. 2
• C. 3
• D. 0

Answer 1

The correct option is B 2


From Grubler's criteria

$F=3(N-l)-2j-h$

$\text{Where}N=\text{Number of links,}$

$j=\text{Number of lower pair,}$

$h=\text{Number of higher pair.}$

Given that:

$N=9,j=11\text{and}h=0$

$F=3(N-1)-2j-h$

$=3(9-1)-2\times 11-0=24-22=2$