The dehydrohalogenation of 2-bromobutane with alcoholic
$K O H$ gives:

Only 2- butene

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Only 1- butene

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2- Butene as the major product

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1- Butene as the major product

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Solution

The correct option is C 2- Butene as the major product

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The dehydrohalogenation of neopentyl bromide with alcoholic KOH mainly gives

Q. Elimination reaction of 2-bromobutane to form but-2-ene is:
(a)

β

-Elimination reaction
(b) Follows Hoffmann rule
(c) Dehydrohalogenation reaction
(d) Dehydration reaction

Q. Which compound gives 2- butene on dehydrohalogenation ?

The back - side attack on 2 - bromobutane by methoxide $(C H_{3} O^{⊖})$ gives the product shown below. Which Fischer projection represents 2 - bromobutane used as the reactant in this reaction?

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The dehydrohalogenation of 2-bromobutane with alcoholic KOH gives:

The correct option is C 2- Butene as the major product

The dehydrohalogenation of 2-bromobutane with alcoholic
$K O H$ gives: