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Question

The ΔH and ΔS for a reaction at one atmospheric pressure are +30.558 kJ and 0.066 k J k1 respectively. The temperature at which the free energy change will be zero and below this temperature the nature of reaction would be:


A

483 K, spontaneous

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B

443 K, non-spontaneous

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C

443 K, spontaneous

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D

463 K, non-spontaneous

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Solution

The correct option is D

463 K, non-spontaneous


Now, to get T, let's use
G = HTS
Here, H=+30.558KJ
S=0.066kJk1
G=0
0=30.558T×0.066
T=30.5580.066=463K
Now, at 463 KG = 0
If we go below 463 K, TS value will decrease and G value will become positive.
Therefore, non-spontaneous


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