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Question

The ΔHf for CO2(g), CO(g) and H2O(g) are - 393.5, -110.5 and - 241.8 KJ mol1 respectively.
The standard enthalpy change (in kJ) for the reaction CO2+H2CO+H2O is:


A
524.1
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B
41.2
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C
-262.5
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D
-41.2
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Solution

The correct option is B 41.2
Given
C+O2CO2; ΔH=393.5kJ ....(i)
C+12O2CO; ΔH=110.5kJ ....(ii)
H2+12O2H2O; ΔH=241.8kJ ....(iii)
By Eqs. (ii) + (iii) - (i)
CO2+H2CO+H2O; ΔH=41.2

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