The denominator of a fraction is 3 more than the numerator. If the numerator as well as the denominator is increased by 4, the fraction becomes $\frac{4}{5}$ . What was the original fraction?

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Solution

The correct option is A

Let the numerator be x. Then, denominator = x + 3.

Now, $\frac{x + 4}{(x + 3) + 4} = \frac{4}{5}$

5 $(x + 4) = 4 (x + 7) \Leftrightarrow x = 8.$

$∴$ The fraction is $\frac{8}{11} .$

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Q. The numerator of a fraction is

5

less than its denominator. If

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is added to the numerator and denominator both, the fraction becomes

\frac{4}{5}

. Find the original fraction.

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\frac{12}{77}

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The denominator of a fraction is 3 more than the numerator. If the numerator as well as the denominator is increased by 4, the fraction becomes45. What was the original fraction?

The correct option is A Let the numerator be x. Then, denominator = x + 3. Now, x+4(x+3)+4=45 5(x+4)=4(x+7)⇔x=8. ∴The fraction is 811.

The denominator of a fraction is 3 more than the numerator. If the numerator as well as the denominator is increased by 4, the fraction becomes $\frac{4}{5}$ . What was the original fraction?

The correct option is A

Let the numerator be x. Then, denominator = x + 3.

Now, $\frac{x + 4}{(x + 3) + 4} = \frac{4}{5}$

5 $(x + 4) = 4 (x + 7) \Leftrightarrow x = 8.$

$∴$ The fraction is $\frac{8}{11} .$