The denominator of a-a2-b2a-a2-b2 - a-a2-b2a-a2-b2 is -

The correct option is B b^2 a+√(a^2 b^2)a √(a^2 b^2)+a √(a^2 b^2)a+√(a^2 b^2) =(a+√(a^2 b^2))^2+(a √(a^2 b^2))^2a^2 (a^2 b^2) =2a^2+2a^2 2b^ ...

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Adding Consecutive Odd Numbers

The denominat...

Question

The denominator of $\frac{a + \sqrt{a^{2} - b^{2}}}{a - \sqrt{a^{2} - b^{2}}} + \frac{a - \sqrt{a^{2} - b^{2}}}{a + \sqrt{a^{2} - b^{2}}}$ is ____.

a^{2}

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b^{2}

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a^{-} b^{2}

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\frac{4 a^{2} - 2 b^{2}}{b^{2}}

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Solution

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Similar questions

\frac{a + \sqrt{a^{2} - b^{2}}}{a - \sqrt{a^{2} - b^{2}}} + \frac{a - \sqrt{a^{2} - b^{2}}}{a + \sqrt{a^{2} - b^{2}}}

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}}

(a^{2} + b^{2}) (a^{2} + b^{2}) - (a^{2} - b^{2}) (a^{2} - b^{2}) = 4 a^{2} b^{2}

a^{2}

b^{2}

16 b^{2} + 9 a^{2} = a^{2} b^{2}

36 b^{2} + 4 a^{2} = a^{2} b^{2}

\frac{a}{b}

\frac{(a sinθ - b cosθ)}{(a \sin θ + b cosθ)}

\frac{(a^{2} + b^{2})}{(a^{2} - b^{2})}

\frac{(a^{2} - b^{2})}{(a^{2} + b^{2})}

\frac{a^{2}}{(a^{2} + b^{2})}

\frac{b^{2}}{(a^{2} + b^{2})}

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