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Graham's Law of Effusion

The densities...

Question

The densities of two gases are in the ratio of $1 : 16$ . The ratio of their rates of diffusion is:

16 : 1

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4 : 1

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1 : 4

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1 : 16

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Solution

The correct option is B $4 : 1$
For the gases to be at same temperature and pressure
$\frac{r_{1}}{r_{2}} = \sqrt{\frac{d_{2}}{d_{1}}}$

= $\sqrt{\frac{16}{1}}$ = 4.:1

Hence, the correct option is $B$

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Similar questions

A

B

4 : 1

Under the same conditions, the rates of diffusion of two gases are in the ratio 1 : 4. The ratio of their vapour densities is ___.

A

B

1 : 2

B

C

1 : 8

C

A

1 : 4

2 : 3

(9^{1 / 3} = 2.08)

A

B

1 : 4

2.3

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