Question

The density of $1$ M solution of $HCl$ is $1.0585$ g/mL. The molality of the solution is:

• A. 1.0585
• B. 1
• C. 0.1
• D. 0.0585

Answer 1

Answer: (B)

1

The expression for the molality M is $\frac{1000M}{(1000d-Mm)}$
Substitute values in the above expression.
$M^{{}^{\prime }}=\frac{1000\times 1}{[1000\times 1.0585-58.5\times 1]}=1.00molk{g}^{-1}$