Question

# The density of $$3\:M$$ solution of $$NaCl$$ is $$1.25\; g \; ml^{-1}$$. The molality of the solution is:

A
2.79 m
B
1.79 m
C
3.5 m
D
5.58 m

Solution

## The correct option is B $$2.79$$ mThe relationship between the density (d), molarity (M), molality (m) and gram molecular weight (GMW) is, $$m= \dfrac {M \times 1000} {1000 \times d -M \times GMW}$$Substituting values in the above expression, we get$$m= \dfrac {3 \times 1000} {1000 \times 1.25 -3 \times 58.5} = 2.79 \:m$$Hence, option A is correct.Chemistry

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