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Question

The density of 3 molal solution of NaOH is 1.110 g mL1. Calculate the molarity of the solution.

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Solution

3 molal solutoin of NaOH means 3 moles of NaOH are dissolved in 1 kg solvent. So, the mass of solution = 1000 g solvent + 120. g NaOH = 1120 g solution

(Molar mass of NaOH = 23 + 16 + 1 = 40 g and 3 moles of NaOH =3×40=120g)

Volume of solution =Mass of solutionDensity of solution (d=mV)

V=1120 g1.110 g mL1=1009 mL

Molarity=Moles of solute×1000Volume of solution(mL)

=3×10001009=2.973 M3M


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