The density of a $3 M$ sodium thiosulphate $(N a_{2} S_{2} O_{3})$ solution is $1.25 g m / m l$ . Calculate the percentage by weight of sodium thiosulphate.

73.92

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65.84

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17.14

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37.92

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Solution

The correct option is D $37.92$
Percentage by weight of sodium thiosulphate solution $(N a_{2} S_{2} O_{3})$ will be:
$= \frac{w t . o f N a_{2} S_{2} O_{3}}{w t . o f s o l u t i o n} \times 100$
Also wt. of $4 N a_{2} S O_{3} =$ Molarity $\times$ molecular wt. $= 3 \times 150$
$%$ by wt. $= \frac{3 \times 158}{1.25 \times 100} \times 100 = 37.92$

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Similar questions

Q. The density of a 3 M sodium thiosulphate solution

(N a_{2} S_{2} O_{3})

1.25 g / m L

. Calculate (i) the percentage by mass of sodium thiosulphate, (ii) the mole fraction of sodium thiosulphate and (iii) molalities of

N a^{+}

and

S_{2} O_{3}^{2 -}

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Q. The density of

3

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The density of 3M aqueous solution of sodium thiosulphate is 1.25g/ml. Calculate (1) mole fraction of sodium thiosulphte (2) molalities of Na^+ and S2O3^-2 ions.

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solution is 1.2 g/mL, then the molality of the solution is:

Q. Find the molality of the thiosulphate

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The density of a 3M sodium thiosulphate (Na2S2O3) solution is 1.25gm/ml. Calculate the percentage by weight of sodium thiosulphate.

The correct option is D 37.92Percentage by weight of sodium thiosulphate solution (Na2S2O3) will be:=wt. of Na2S2O3wt. of solution×100Also wt. of 4Na2SO3=Molarity× molecular wt.=3×150% by wt.=3×1581.25×100×100=37.92

The density of a $3 M$ sodium thiosulphate $(N a_{2} S_{2} O_{3})$ solution is $1.25 g m / m l$ . Calculate the percentage by weight of sodium thiosulphate.