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Question

The density of a 30% by mass solution of acetic acid in water is 1.250 g/mL. Its molarity is:

A
2.5 M
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B
12.5 M
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C
6.25 M
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D
1.25 M
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Solution

The correct option is C 6.25 M
Assuming 1000 mL of the solution.
Mass of the solution = 1.250×1000=1250 g
Mass of acetic acid = 1250×30100=375 g
Molar mass of acetic acid = 60 g
Thus, moles of acetic acid = 37560
Hence, the molarity of the solution,
= 375601=6.25 M

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