Question

The density of a gas at ${27}^{0}C$ and 1 atm is d. Pressure remaining constant at what temperature will it's density becomes 0.75 d

• A. ${36}^{0}C$
• B. ${127}^{0}C$
• C. ${30}^{0}C$
• D. ${54}^{0}C$

Answer 1

The correct option is B ${127}^{0}C$

$d=\frac{PM}{RT}$
$\frac{d_1}{d_2}=\frac{T_2}{T_1}$
$\frac{d}{0.75d}=\frac{T_2}{300}$
$T_2=400k={127}^{0}C$