Question

The density of a gas at ${27}^{\circ }C$ and $1atm$ is ${}^{\prime }{d}^{\prime }$. Pressure remaining constant, the temperature at which its density becomes $0.75d$ is:

• A. ${20}^{\circ }C$
• B. ${30}^{\circ }C$
• C. $400K$
• D. $300K$

Answer 1

The correct option is C $400K$

$P=\frac{dRT}{M}$

When, $P$ is constant, $dT=$ constant

$\therefore d\times 300=0.75d\times T$

$\therefore T=\frac{300}{0.75}=400$ $K$