The density of a gas at temperature 283.2 k is 25 g/cc. At what temperature will its density become 24 g/cc,if the pressure is kept constant?

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Solution

The correct option is A
At constant pressure,
$D_{1} T_{1} = D_{2} T_{2} o r 25 \times 283.2 = 24 \times T_{2}$
$\Rightarrow T_{2} = \frac{25 \times 283.2}{24} = 295 K$
$∴$ Temperature in centigrade is 295 – 273
= $22^{\circ}$

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The density of a gas at temperature 283.2 k is 25 g/cc. At what temperature will its density become 24 g/cc,if the pressure is kept constant?

The correct option is A At constant pressure, D1T1=D2T2or25×283.2=24×T2 ⇒T2=25×283.224=295K ∴ Temperature in centigrade is 295 – 273 =22∘

The correct option is A
At constant pressure,
$D_{1} T_{1} = D_{2} T_{2} o r 25 \times 283.2 = 24 \times T_{2}$
$\Rightarrow T_{2} = \frac{25 \times 283.2}{24} = 295 K$
$∴$ Temperature in centigrade is 295 – 273
= $22^{\circ}$