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Ideal Gas Equation

The density o...

Question

The density of a gas is $2.5$ g/L at $127^{0}$ C and $1$ atm. The molecular weight of the gas is:

82.1

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41.05

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56

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28

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Solution

The correct option is A $82.1$
$P V = n R T$
$\Rightarrow P = \frac{n}{V} R T = \frac{W}{M V} R T = \frac{d}{M} R T$
$∴$ $P = \frac{d}{M} R T \Rightarrow M = \frac{d R T}{P}$
$\Rightarrow M = \frac{2.5 g m / l i t \times 0.0821 L i t - a t m / K - m o l \times 400 K}{1 a t m}$
$\Rightarrow M = 82.1 g m / m o l$ .

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