Question

The density of a gas is found to be $5.46\mathrm{g}/{\mathrm{dm}}^3\mathrm{at}27°\mathrm{C}\mathrm{at}2$bar pressure. What will be its density at STP?

Answer 1

Step 1:Given data:

d₁ =$5.46\mathrm{g}/{\mathrm{dm}}^3$

p₁ =$2\mathrm{bar}$

T₁ = $27°C=(27+273)K=300K$

p₂ = $1\mathrm{bar}$

T₂ = $273K$

d₂ = ?

Step 2: Formula used

Ideal gas law , $\mathrm{PV}=\mathrm{nRT}$

Density = $\frac{\mathrm{Mass}}{\mathrm{Volume}}$

Step 3: Calculation of the density :

Calculation of the density(d₂) of the gas at STP , which can be calculated using the equation,

Density =$\frac{(1x300x5.46)}{2}x273$

We get,

= $3\mathrm{g}{\mathrm{dm}}^{-3}$

Therefore, the density of the gas at STP will be $3\mathrm{g}{\mathrm{dm}}^{-3}$.