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Question

The density of a metal at normal pressure is ρ, Its density when it is subjected to an excess pressure P is ρ. If bulk modulus of metal is 2P then ρρ is:

A
2
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B
12
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C
13
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D
3
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Solution

The correct option is A 12
As we know that
K=VdPdV

but for constant mass dVV=dρρ
so, K=ρdPdρ

given that K=2P and when dP=P then above equation becomes,
2P=ρPdρ

dρ=ρ2

ρρ=ρ2
(where, ρ=final density and ρ= initial density)

ρρ=12

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