The density of a polyatomic gas in standard conditions is 0.795kg/m3. The specific heat of the gas at constant volume is
A
930J/kgK
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B
1400J/kgK
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C
1120J/kgK
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D
1600J/kgK
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Solution
The correct option is B1400J/kgK For given polyatomic gas, applying ideal gas equation PM=dRT under standard conditions, where P=pressure=1atm, M=molar mass, d=density=0.795kg/m3,
R=universal gas constant,
T=absolute temperature=273K
M=0.795×8.31×273100000=0.018kg=18g Hence, molecule is H2O⇒ degree of freedom =6 ⇒ specific heat at constant volume=Cv=f2R=3R=3×8.31×100018=1400J/kgK