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Question

The density of a pure substance ‘A’, whose atoms are arranged in a cubic close pack arrangement, is 1g/cc. If all the tetrahedral voids are now filled with ‘B’ atoms, what is the density of the resulting solid in g/cc? [Molar mass A=30g/mol and Molar mass B = 50 g/mol]

A
3.33
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B
4.33
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C
2.33
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D
5.33
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Solution

The correct option is B 4.33
We know that density can be given by:
ρ=nMVNA
For pure A, 1=4×30VNA
V=120NA
ρ=4×30+8×50120
ρ=4.33g/cc

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