The density of a solution prepared by dissolving $120 g$ of urea (mol. mass $= 60 u$ ) in $1000 g$ of water is $1.15 g {m L}^{- 1}$ . The molarity of the solution is:

0.50 M

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1.78 M

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1.02 M

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2.05 M

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Solution

The correct option is D $2.05 M$
Density $= \frac{m a s s}{v o l u m e}$

$= \frac{1000 + 120}{v o l u m e}$

Density of the solution $= 1.15 g / m L$

Volume $= \frac{1000 + 120}{1.15} = 973.91 m L$

Molarity $= \frac{M o l e s}{V o l u m e i n L i t r e s}$

$= \frac{120 \times 1000}{60 \times 973.91} = 2.05 M$

Hence, the correct option is $D$

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