Question

The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60 g/mol) in 1000 g of water is 1.15 g/mL. The molarity of this solution is

• A. 1.78 M
• B. 1.02 M
• C. 2.05 M
• D. 0.50M

Answer 1

The correct option is C 2.05 M

Total weight of solution = 1000 + 120 =1120g
Molarity $=\frac{120}{60}\times \frac{1000\times 1.15}{1120}=2.05M$