wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The density of a substance at 20C and 120C are 1.1g c.c1 and 1 g c.c1 respecttively. Find the coefficient of cubical expansion of the solid.


A

0.001/C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

0.002/C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.003/C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

0.004/C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

0.001/C


Given: Initial density, d1=1.1 g c.c1
Final density, d2=1 g c.c1
Initial tempereature, t1=20C
Final temperature, t2=120C

Volumetric expansion of solids can be expressed as,
V2=V1(1+γ(t2t1))
where, V1 is the initial volume, V2 is the final volume, t1 is the initial temperature, t2 is the final temperature and γ is the coefficient of cubical expansion of solid.
We know volume=massdensity
Let d1 be the density at volume V1 and d2 be the density at volume V2
Since mass of the substance, m remains same, we have,
or, md2=md1(1+γ(t2t1))
or, γ=d1d2d2(t2t1)
or, γ=1.111(12020)=0.1100=0.001
γ=0.001C1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Gestation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon