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Question

The density of air is 0.001293 g/cc at S.T.P. Its vapour density is ___________.

A
0.001293
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B
8.2786
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C
14.48
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D
6.2706
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Solution

The correct option is C 14.48
Explanation:

We know that: Molecular Mass= 2x Vapour Density

At STP or under standard conditions of pressure and temperature, 22.4 l of any gas equals to 1 mole.

That is, 1 mole = 22.4 l

The density of air is given as 0.001293g/ml

The volume of gas=22400 ml

We know that mass= density x volume

Therefore, rearranging the above equation, Mass= 0.001293 x 22400= 28.96 g

Also we know that, Molecular Mass= 2 x Vapour Density

Rearranging the equation we get,

Vapour Density= Molecular Mass ÷ 2

=28.96÷2=14.48 gm
Option C is correct answer

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