The density of air is 0.001293 g/ml at STP. Its vapour density will be:

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1.44

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14.4

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Solution

The correct option is A 14.4
Given density $= 0.001293$ g/ml
1 ml contains $0.001293$ g, thus $22400$ ml will contain $0.001293 \times 22400 = 28.96$ g.
Hence, molecular weight of air $= 28.96$ g
$∴$ vapour density $= \frac{molecular mass}{2} \approx 14.4$ g

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