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Question

The density of air is 0.001293 g/cm3 at STP. Which of the following statements is/are correct?

A
Vapour density is 14.48
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B
Molecular weight is 28.96 amu
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C
Vapour density is 0.001293
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D
Vapour density and molecular weight cannot be determined
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Solution

The correct options are
A Vapour density is 14.48
B Molecular weight is 28.96 amu
We know that: Molecular mass (Numerical value)=2×Vapour density
At STP or under standard conditions of pressure and temperature, 22.4 L of any gas is equal to 1 mole.
Therefore 1 mole = 22.4 L
The Volume of gas = 22400 mL
We know that mass=density×volume
Therefore, rearranging the above equation
Mass = 0.001293×22400=28.96 g
Hence, molecular mass is 28.96
Also, we know that, Molecular mass (Numerical value)=2×Vapour density
Rearranging the equation, we get,
Vapour density =Molecular mass (Numerical value)2
=28.962=14.48

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