The density of an aqueous suggestion of H2S offer is 1.05 gram per mole and the solution contains 14% of H2S o4 by mass the molarity of the solution is

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Solution

Dear student,

14% solution of H₂SO₄ means that 14 g H₂SO₄ is present in 100 g solvent i.e. 14 g H₂SO₄ is present and 86 g of solvent is present.
Density of solution = $(\frac{M a s s}{V o l u m e})$
Volume = $(\frac{M a s s}{D e n s i t y}) = \frac{100 g}{1.05 g / m L} = 95.238 m L$
So, 95.238 mL of solution contains 14 g H₂SO₄
1 mL of solution will contain $\frac{14}{95.238} g o f s u l p h u r i c a c i d$
1000 mL will have $\frac{14}{95.238} \times 1000 g s u l p h u r i c a c i d$ = 147.0 f of sulphuric acid
Molarity = $\frac{M o l e o f s u l p h u r i c a c i d}{V o l u m e o f s o l v e n t i n L} = \frac{147.0 / 98}{1 L} = 1.5 M$
Regards

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