The density Of an ideal gas is 1-25 - 10-3 g cm at STP- Calculate the molecular weight of the gas-

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Standard XII

Physics

Ideal Gas Equation from KTG

The density O...

Question

The density Of an ideal gas is 1.25 $\times 10^{- 3}$ g cm at STP. Calculate the molecular weight of the gas.

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Solution

From teh formula

PV= nRT = $\frac{m}{M}$ RT .... (1)

where

m = mass of the gas
M = molecular weigth of the gas

From equation (1),

P = $(\frac{m}{M}) \frac{R T}{V} = \frac{d R T}{M}$

$∴ M = \frac{d R T}{P} = \frac{125 \times 10^{3} \times 8.3 \times 273}{10^{5}}$

= 28.3 g/mol

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The density Of an ideal gas is 1.25 ×10−3 g cm at STP. Calculate the molecular weight of the gas.

From teh formula PV= nRT = mM RT .... (1) where m = mass of the gas M = molecular weigth of the gas From equation (1), P = (mM)RTV=dRTM ∴M=dRTP=125×103×8.3×273105 = 28.3 g/mol

The density Of an ideal gas is 1.25 $\times 10^{- 3}$ g cm at STP. Calculate the molecular weight of the gas.

From teh formula

PV= nRT = $\frac{m}{M}$ RT .... (1)

where

m = mass of the gas
M = molecular weigth of the gas

From equation (1),

P = $(\frac{m}{M}) \frac{R T}{V} = \frac{d R T}{M}$

$∴ M = \frac{d R T}{P} = \frac{125 \times 10^{3} \times 8.3 \times 273}{10^{5}}$

= 28.3 g/mol