The density of copper is 3 g cm -3- Express it in kg m -3-A- 3B- 30C- 300D- 3000

The correct option is D 3000Density of copper, ρ_c = 3 g/cm^3 ρ_c = 3 ×1/1000 kg( 1/100 m )^3 ρ_c = 3 × 10^ 3× 10^6 kg m^ 3 ρ_c = 3 × 10^3 kg m^ 3 ρ_c = 3000 ...

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Standard VIII

Physics

Density

The density o...

Question

The density of copper is $3 g c m^{- 3}$ . Express it in $k g m^{- 3}$ .

3

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30

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300

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3000

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Solution

The correct option is D $3000$
Density of copper,
$ρ_{c} = 3 g / c m^{3}$
$ρ_{c} = 3 \times \frac{\frac{1}{1000} k g}{{(\frac{1}{100} m)}^{3}}$
$ρ_{c} = 3 \times 10^{- 3} \times 10^{6} k g m^{- 3}$
$ρ_{c} = 3 \times 10^{3} k g m^{- 3}$
$ρ_{c} = 3000 k g m^{- 3}$

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The density of copper is 3 g cm−3. Express it in kg m−3.

The correct option is D 3000Density of copper, ρc=3 g/cm3 ρc=3×11000 kg(1100 m)3 ρc= 3×10−3×106 kg m−3 ρc=3×103 kg m−3 ρc=3000 kg m−3

The density of copper is $3 g c m^{- 3}$ . Express it in $k g m^{- 3}$ .

The correct option is D $3000$
Density of copper,
$ρ_{c} = 3 g / c m^{3}$
$ρ_{c} = 3 \times \frac{\frac{1}{1000} k g}{{(\frac{1}{100} m)}^{3}}$
$ρ_{c} = 3 \times 10^{- 3} \times 10^{6} k g m^{- 3}$
$ρ_{c} = 3 \times 10^{3} k g m^{- 3}$
$ρ_{c} = 3000 k g m^{- 3}$