The density of ice is $0.921 g c m^{- 3}$ . Calculate the mass of a cubic block of ice which is $76 m m$ on each side.

49 g

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4 \times 10^{2} g

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0.04 g

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4 \times 10^{3} g

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Solution

The correct option is B $4 \times 10^{2} g$
Now, 1 $m m$ = 0.1 $c m$
$∴$ 76 $m m$ = 7.6 $c m$
Volume of cube $=$ $(7.6)^{3}$ $=$ 438. 98 $c m^{3}$
Now, mass $=$ density $\times$ volume $=$ 0.921 $\times$ 438.98 $=$ 404 $g$ $=$ $4.04 \times 10^{2} g$

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The density of ice is 0.921g cm−3. Calculate the mass of a cubic block of ice which is 76mm on each side.

The correct option is B 4×102gNow, 1 mm = 0.1 cm∴ 76mm = 7.6 cmVolume of cube = (7.6)3 = 438. 98 cm3Now, mass = density × volume = 0.921 × 438.98 = 404 g = 4.04×102g

The density of ice is $0.921 g c m^{- 3}$ . Calculate the mass of a cubic block of ice which is $76 m m$ on each side.

The correct option is B $4 \times 10^{2} g$
Now, 1 $m m$ = 0.1 $c m$
$∴$ 76 $m m$ = 7.6 $c m$
Volume of cube $=$ $(7.6)^{3}$ $=$ 438. 98 $c m^{3}$
Now, mass $=$ density $\times$ volume $=$ 0.921 $\times$ 438.98 $=$ 404 $g$ $=$ $4.04 \times 10^{2} g$