The density of ice is $917 k g m^{- 3}$ . What fraction of the volume of a piece of ice will be above water, when floating in fresh water?

0.06

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0.083

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0.038

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0.068

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Solution

The correct option is B 0.083
Acc. to Archemedes principal

$ρ_{1} v g = P_{2} v_{i} g$

$\frac{v_{i}}{v} = \frac{f_{1}}{ρ_{2}} = \frac{917}{1000} = 0.917$

Fraction outside water $= 0.083$

Answer $(B) 0.083$

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