The density of ice is $x g / L$ and that of water is $y g / L$ . What is the change in volume when $m$ gram of ice melts?

m x y (x - y)

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\frac{m}{(y - x)}

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m (\frac{1}{y} - \frac{1}{x})

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\frac{y - x}{x}

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Solution

The correct option is B $m (\frac{1}{y} - \frac{1}{x})$
Volume of $m g$ of ice $= m / x$ and
volume of $m g$ of water $= m / y$ . So change in volume
$\frac{m}{y} - \frac{m}{x}$ = m $(\frac{1}{y} - \frac{1}{x})$

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The density of ice is x g/L and that of water is y g/L. What is the change in volume when m gram of ice melts?

The correct option is B m(1y−1x)Volume of m g of ice =m/x andvolume of m g of water =m/y. So change in volume my−mx = m (1y−1x)

The density of ice is $x g / L$ and that of water is $y g / L$ . What is the change in volume when $m$ gram of ice melts?

The correct option is B $m (\frac{1}{y} - \frac{1}{x})$
Volume of $m g$ of ice $= m / x$ and
volume of $m g$ of water $= m / y$ . So change in volume
$\frac{m}{y} - \frac{m}{x}$ = m $(\frac{1}{y} - \frac{1}{x})$