The density of ice is $x g m / c c$ and that of water is $y g m / c c$ . What is the change in volume in $c c$ , when $m g m$ of ice melts?

m (y - x)

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(y - x) / m

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m x y (x - y)

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m (1 / y - 1 / x)

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Solution

The correct option is D $m (1 / y - 1 / x)$
After mgm of ice melts. then $\frac{m}{x}$ volume of ice reduces & $\frac{m}{y}$ volume of water increases
So change in volume = $\frac{m}{y} - \frac{m}{x}$
= $m (\frac{1}{y} - \frac{1}{x}) c c .$

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The density of ice is x gm/cc and that of water is y gm/cc. What is the change in volume in cc, when m gm of ice melts?

The correct option is D m(1/y−1/x)After mgm of ice melts. then mx volume of ice reduces & my volume of water increasesSo change in volume = my−mx = m(1y−1x)cc.

The density of ice is $x g m / c c$ and that of water is $y g m / c c$ . What is the change in volume in $c c$ , when $m g m$ of ice melts?

The correct option is D $m (1 / y - 1 / x)$
After mgm of ice melts. then $\frac{m}{x}$ volume of ice reduces & $\frac{m}{y}$ volume of water increases
So change in volume = $\frac{m}{y} - \frac{m}{x}$
= $m (\frac{1}{y} - \frac{1}{x}) c c .$