The density of ice is $x g m / c m^{3}$ and that of water is $y g m / c m^{3}$ . When $m$ gram of ice melts, then the change in volume is

m (y - x)

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(y - x) / m

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m y (x - y)

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(m / y) - (m / x)

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Solution

The correct option is D $(m / y) - (m / x)$
Volume of ice = $\frac{m a s s}{d e n s i t y} = \frac{m}{x}$ $c m^{3}$
Volume of water $= \frac{m}{y}$ $c m^{3}$
Thus change in volume = final volume - initial volume
Change in volume $= \frac{m}{y} - \frac{m}{x}$

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The density of ice is x gm/cm3 and that of water is y gm/cm3. When m gram of ice melts, then the change in volume is

The correct option is D (m/y)−(m/x)Volume of ice = massdensity=mx cm3 Volume of water =my cm3 Thus change in volume = final volume - initial volume Change in volume =my−mx

The density of ice is $x g m / c m^{3}$ and that of water is $y g m / c m^{3}$ . When $m$ gram of ice melts, then the change in volume is

The correct option is D $(m / y) - (m / x)$
Volume of ice = $\frac{m a s s}{d e n s i t y} = \frac{m}{x}$ $c m^{3}$
Volume of water $= \frac{m}{y}$ $c m^{3}$
Thus change in volume = final volume - initial volume
Change in volume $= \frac{m}{y} - \frac{m}{x}$