The density of ice is $x g m / c m^{3}$ and that of water is $y g m / c m^{3}$ . When $m$ gram of ice melts, then the change in volume is

m (y - x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(y - x) / m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m y (x - y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(m / y) - (m / x)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $(m / y) - (m / x)$
Volume of ice = $\frac{m a s s}{d e n s i t y} = \frac{m}{x}$ $c m^{3}$
Volume of water $= \frac{m}{y}$ $c m^{3}$
Thus change in volume = final volume - initial volume
Change in volume $= \frac{m}{y} - \frac{m}{x}$

Suggest Corrections

Similar questions

Q. The density of ice is

x g m / c m^{3}

and that of water is

y g m / c m^{3}

. When

m

gram of ice melts, then the change in volume is

The density of ice is x gm/cc and that of water is y gm/cc . What is the change in volume in cc when m gm of ice melts ?

Q. The density of ice is x gm/cc and that of water is y gm/cc What is the change in volume in cc, when m gm of ice melts?

Q. The density of ice is

x g / L

and that of water is

y g / L

. What is the change in volume when

m

gram of ice melts?

1)A vessel contains oil (density 0.8 g/cc) over Mercury( density 13.6 g/cc).a homogeneous sphere floats with half its volume immersed in Mercury and the othe half in the oil .the density of the material of the sphere in g/cc is.

2) the density of ice is Y gram/litre and that of water is X gram/litre. what is the change in volume when M gram of ice melts.

Join BYJU'S Learning Program

The density of ice is x gm/cm3 and that of water is y gm/cm3. When m gram of ice melts, then the change in volume is

The correct option is D (m/y)−(m/x)Volume of ice = massdensity=mx cm3 Volume of water =my cm3 Thus change in volume = final volume - initial volume Change in volume =my−mx

The density of ice is $x g m / c m^{3}$ and that of water is $y g m / c m^{3}$ . When $m$ gram of ice melts, then the change in volume is

The correct option is D $(m / y) - (m / x)$
Volume of ice = $\frac{m a s s}{d e n s i t y} = \frac{m}{x}$ $c m^{3}$
Volume of water $= \frac{m}{y}$ $c m^{3}$
Thus change in volume = final volume - initial volume
Change in volume $= \frac{m}{y} - \frac{m}{x}$