Question

The density of mercury is $13.6g/{cm}^3$. Estimate the $b$ value.

• A. 58.6 /cm
• B. 60 /cm
• C. 50 /cm
• D. 24.6 /cm

Answer 1

Answer: (A)

58.6 /cm

$r^3$ = $\frac{3M}{4\pi d{N}_A}$

= $\frac{3\times 200}{4\times 3.1416\times 13.6\times 6.023\times {10}^{23}}$

=$5.83\times {10}^{-24}$

b = $\frac{4}{3}$ $\pi r^3\times 4N_A$

= $\frac{4}{3}$ $\times 3.1416\times 5.8\times {10}^{-24}\times 4\times 6.023\times {10}^{23}$

= 58.6 /cm