The density of nitrogen under standard conditions is:

2.5 g/ L

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1.25 g/ L

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0.625 g/ L

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3.75 g/ L

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Solution

The correct option is B 1.25 g/ L
At standard conditions $1$ mole of $N_{2}$ will occupy $22.4 l$ of volume.

So, $22.4 l$ will contain $(2 \times 14) = 28$ g Nitrogen= mass of $N_{2}$

$∴$ density $= \frac{M}{V} = \frac{28}{22.4} = 1.25$ g/L

Hence, option $B$ is correct.

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