The density of oxygen is $1.54 g L^{- 1}$ at STP. Determine the density of oxygen at $17^{\circ} C$ and $800 t o r r$ .

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Solution

$d = \frac{M P}{R T}$
At STP, $d_{1} = \frac{M P_{1}}{R T_{1}}$
$[P_{1} = 760 t o r r, T_{1} = 273 K; d_{1} = 1.43 g L^{- 1}]$

Given conditions,
$d_{2} = \frac{M P_{2}}{R T_{2}} [P_{2} = 800 t o r r, T_{2} = 290 K; d_{2} = ?]$
So, $\frac{d_{2}}{d_{1}} = \frac{P_{2}}{T_{2}} \times \frac{T_{1}}{P_{1}}$
$d_{2} = \frac{P_{2}}{P_{1}} \times \frac{T_{1}}{T_{2}} \times d_{1}$
$= \frac{800}{760} \times \frac{273}{290} \times 1.43 = 1.417 g L^{- 1}$ .

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