The density of water at 4-C is 1000 kg m-3 and at 104-C it is 958-4 kg m-3- The cubic expansivity of water between these temperature is

The correct option is C 4.16× 10^ 4(^∘C)^ 1 ρ =ρ _0(1 γΔ T) ∴γ =ρ _0 ρ/ρ _0Δ T=1000 958.4/(100)(1000) =4.16× 10^ 4(^∘C)^ 1 ...

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Standard XII

Physics

Thermal Expansion

The density o...

Question

The density of water at $4^{\circ} C$ is $1000 k g m^{- 3}$ and at $104^{\circ} C$ it is $958.4 k g m^{- 3}$ . The cubic expansivity of water between these temperature is

4.16 \times 10^{- 5} (K)^{- 1}

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2.08 \times 10^{- 5} (^{\circ} C)^{- 1}

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4.16 \times 10^{- 4} (^{\circ} C)^{- 1}

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2.08 \times 10^{- 4} (K)^{- 1}

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Solution

The correct option is C $4.16 \times 10^{- 4} (^{\circ} C)^{- 1}$
$ρ = ρ_{0} (1 - γ Δ T)$
$∴ γ = \frac{ρ_{0} - ρ}{ρ_{0} Δ T} = \frac{1000 - 958.4}{(100) (1000)}$
$= 4.16 \times 10^{- 4} (^{\circ} C)^{- 1}$

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The density of water at 4∘C is 1000kgm−3 and at 104∘C it is 958.4kgm−3. The cubic expansivity of water between these temperature is

The correct option is C 4.16×10−4(∘C)−1ρ=ρ0(1−γΔT)∴γ=ρ0−ρρ0ΔT=1000−958.4(100)(1000)=4.16×10−4(∘C)−1

The density of water at $4^{\circ} C$ is $1000 k g m^{- 3}$ and at $104^{\circ} C$ it is $958.4 k g m^{- 3}$ . The cubic expansivity of water between these temperature is

The correct option is C $4.16 \times 10^{- 4} (^{\circ} C)^{- 1}$
$ρ = ρ_{0} (1 - γ Δ T)$
$∴ γ = \frac{ρ_{0} - ρ}{ρ_{0} Δ T} = \frac{1000 - 958.4}{(100) (1000)}$
$= 4.16 \times 10^{- 4} (^{\circ} C)^{- 1}$