The depression in freezing point for 1 M urea, 1 M glucose and 1M $N a C l$ are in the ratio:

1 : 2 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 : 2 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 1 : 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 : 3 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1 : 1 : 2$
$Δ T_{f} = i K_{f} m_{s o l u t e}$

$Δ T_{f_{1}} : Δ T_{f_{2}} : Δ T_{f_{3}} = i_{1} : i_{2} : i_{3}$

$i_{1} = 1$
$i_{2} = 1$
$i_{3} = 2$

so $Δ T_{f_{1}} : Δ T_{f_{2}} : Δ T_{f_{3}} = 1 : 1 : 2$

Hence, the correct option is $C$

Suggest Corrections

Similar questions

Q. The depressions in freezing point for 1 m urea, 1 m glucose and 1 m NaCl are in the ratio:

0.01 M solutions of urea, common salt and sodium sulphate are taken The ratio of depression of freezing point will be in the ratio

Three different objects of mass $m_{1}$ , $m_{2}$ and $m_{3}$ are allowed to fall from rest and from the same point along three different frictionless paths. The speed of the three objects on reaching the ground will be in the ratio of

Q. The relationship between osmotic pressure at 273 K when 10 g glucose, 10 g urea and 10 g sucrose are dissolved in 250 mL of water to form separate solutions is:
[

P_{1}, P_{2}

and

P_{3}

are osmotic pressure of glucose,urea and sucrose solution respectivitely]

Q. Three black bodies are such that maximum intensity wavelength are in the ratio

λ_{m 1} : λ_{m 2} : λ_{m 3} = 1 : (15)^{1 / 2} : (7)^{1 / 2}

.
Which of the following is true for the temperatures?

Join BYJU'S Learning Program

The depression in freezing point for 1 M urea, 1 M glucose and 1M NaCl are in the ratio:

The correct option is C 1:1:2ΔTf=iKfmsoluteΔTf1:ΔTf2:ΔTf3=i1:i2:i3i1=1i2=1i3=2so ΔTf1:ΔTf2:ΔTf3=1:1:2Hence, the correct option is C

The depression in freezing point for 1 M urea, 1 M glucose and 1M $N a C l$ are in the ratio:

The correct option is C $1 : 1 : 2$
$Δ T_{f} = i K_{f} m_{s o l u t e}$

$Δ T_{f_{1}} : Δ T_{f_{2}} : Δ T_{f_{3}} = i_{1} : i_{2} : i_{3}$

$i_{1} = 1$
$i_{2} = 1$
$i_{3} = 2$

so $Δ T_{f_{1}} : Δ T_{f_{2}} : Δ T_{f_{3}} = 1 : 1 : 2$

Hence, the correct option is $C$