wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The depression in freezing point of 0.01 M aqueous solution of urea, sodium chloride and sodium sulphate are in the ratio:

A
1:1:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:2:3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1:2:4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2:2:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1:2:3
Freezing point depression of a solution is given by,
Tf=i×Kf×m
where,
i is van't Hoff factor
Tf is the depression in freezing point.
Kf is molal depression constant.
m is molality of the solution.
Since all the solutions are of 0.01 M, the depression in freezing point depends on the van't Hoff factor.

Number of ions formed,
For urea, i=1 it is a non-electrolyte
NaCl, i=2
Na2SO4, i=3

Number of ions formed,
Urea: NaCl :Na2SO4

0.01mol:(0.01×2mol):(0.01×3mol)

1:2:3

Thus, ΔTf is also in the same ratio.


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Van't Hoff Factor
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon