The depth of the dam is 240 m. The pressure of water is

(Take g=10 m/s2, density of liquid= 1000 kg/m3)

Open in App

Solution

P = hdg

h is depth.
d is density.

= 240* 1000 * 10 Pa

= 2400000Pa

= 2.4 * 10^6 Pa

Suggest Corrections

Similar questions

Q. If pressure at half depth of a lake is equal to

\frac{2}{3} r d

pressure at the bottom of the lake, then what is the depth of the lake?
(Take atmospheric pressure as

10^{5} Pa

, density of water as

1000 {kg/m}^{3}

and

g = 10 {m/s}^{2}

)

Q. What is the pressure at a point

10 m

below the surface of a lake(see fig)?
Take

g = 10 m s^{- 2}; 1 a t m = 1.01 \times 10^{5} P a

;
Density of water

= 1000 k g / m^{3}

___ $P a$ is the pressure at a depth of $10 m$ below the surface of the kerosene. The density of kerosene is $800 k g / m^{3}$ . Take $g$ = $10 m / s^{2}$

Q. Find the pressure at a depth of

0.6 m

in water of density

1000 k g

m^{- 3}

.(Take

g = 10 m

s^{- 1}

)

The maximum value of water pressure in the box in which water is filled upto a height of $4 m$ is equal to (atmospheric pressure $= 10^{5} N / m^{2},$ density of water $= 1000 k g / m^{3}$ , $g = 10 m / s^{2}$ )

Join BYJU'S Learning Program

The depth of the dam is 240 m. The pressure of water is (Take g=10 m/s2, density of liquid= 1000 kg/m3)

P = hdg h is depth. d is density. = 240* 1000 * 10 Pa = 2400000Pa = 2.4 * 10^6 Pa

The maximum value of water pressure in the box in which water is filled upto a height of 4 m is equal to (atmospheric pressure =105 N/m2, density of water =1000 kg/m3, g=10 m/s2)

The depth of the dam is 240 m. The pressure of water is

(Take g=10 m/s2, density of liquid= 1000 kg/m3)

P = hdg

h is depth.
d is density.

= 240* 1000 * 10 Pa

= 2400000Pa

= 2.4 * 10^6 Pa

The maximum value of water pressure in the box in which water is filled upto a height of $4 m$ is equal to (atmospheric pressure $= 10^{5} N / m^{2},$ density of water $= 1000 k g / m^{3}$ , $g = 10 m / s^{2}$ )