wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The derivative of fx=x2x31loge t dt, x>0, is

(a) 13 ln x

(b) 13 ln x-12 ln x

(c) (ln x)−1 x (x − 1)

(d) 3x2ln x

Open in App
Solution

(c) (ln x)−1 x (x − 1)

Using Newton Leibnitz formula

f'(x)=1logex3(3x2)1logex2(2x)=3x23lnx2x2lnx=x2lnxxlnx=1lnxx(x1)=(lnx)1x(x1)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration of Irrational Algebraic Fractions - 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon