-The derivative of-cosh-1x-with respect to-logx-at-x-5-is-

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Standard Formulae - 1

The derivativ...

Question

The derivative of \operatorname{cosh^{-1x with respect to \operatorname{logx at x=5 is

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A

\frac{{tan}^{- 1} x}{1 + {tan}^{- 1} x}

{tan}^{- 1} x

\frac{1}{(1 + {tan}^{- 1} x)^{2}}

R

\frac{x}{1 + x}

x

\frac{1}{(1 + x)^{2}}

(sin x)^{{cos}^{- 1} x}

x

{tan}^{- 1} \frac{\sqrt{1 + x^{2}} - 1}{x}

{tan}^{- 1} x

{sin}^{- 1} (3 x - 4 x^{3})

{sin}^{- 1} x

{sin}^{- 1} x

{cos}^{- 1} \sqrt{1 - x^{2}}

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