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Question

The derivative of sin3x with respect to lnx is

[2 marks]

A
xsin2xcosx
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B
3xsin2xcosx
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C
3xsin2x
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D
3sin2xcosx
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Solution

The correct option is B 3xsin2xcosx
Let y=sin3x and z=lnx
dydx=3sin2xcosx
and dzdx=1x
Now, dydz=dy/dxdz/dx=3sin2xcosx1/x
dydz=3xsin2xcosx

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