1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Vector Addition
The derivativ...
Question
The derivatives of
sec
−
1
[
1
(
2
x
2
−
1
)
]
with respect to
√
1
−
x
2
at
x
=
1
2
, is
Open in App
Solution
Putting
x
=
cos
θ
, we get
u
=
sec
−
1
1
2
cos
2
θ
−
1
=
sec
−
1
(
sec
2
θ
)
=
2
θ
and
y
=
√
1
−
x
2
=
sin
θ
∴
u
=
2
sin
−
1
y
⇒
d
u
d
y
=
2
√
1
−
y
2
=
2
√
x
2
Thus,
d
u
d
y
∣
∣
∣
x
=
1
/
2
=
4
Suggest Corrections
0
Similar questions
Q.
The derivative of
cos
-
1
2
x
2
-
1
with respect to
cos
-
1
x
is
(a) 2
(b)
1
2
1
-
x
2
(c)
2
/
x
(d)
1
-
x
2
Q.
The derivative of
tan
−
1
(
√
1
+
x
2
−
1
x
)
with respect to
tan
−
1
(
2
x
√
1
−
x
2
1
−
2
x
2
)
at
x
=
0
is
Q.
The derivative of
t
a
n
−
1
(
√
1
+
x
2
−
1
x
)
with respect to
t
a
n
−
1
(
2
x
√
1
−
x
2
1
−
2
x
2
)
at x = 0, is
Q.
The derivative of
s
e
c
−
1
(
1
2
x
2
−
1
)
with respect to
√
1
−
x
2
at
x
=
1
, is
Q.
The derivative of
c
o
s
e
c
−
1
(
1
2
x
2
−
1
)
with respect to
√
1
−
x
2
at
x
=
1
2
is
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Basic Operations
PHYSICS
Watch in App
Explore more
Vector Addition
Standard XII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Solve
Textbooks
Question Papers
Install app